Python OpenPyxl：如何遍历 1 Row 的列以查找值

Question

When using Python OpenPyxl, how would I iterate through 1 Row's columns to find a value?

Here's my current (failing) attempt -- (There appears to be an error in (at least) my 2nd for loop.)

 book = openpyxl.load_workbook(excelFile) for sheet in book.worksheets: #For each worksheet for colidx in sheet.iter_cols(sheet.min_col,sheet.max_col): #For each column in a worksheet if sheet.cell(1,colidx).value == "ValueImLookingFor": #Check each column in Row #1 for value print ("ValueImLookingFor is in cell A" + colidx)

Thanks so much for your help,

CG

Answer 1

Try this:

from openpyxl import load_workbook
wb = load_workbook('C:/Users/viupadhy/Desktop/Results.xlsx')
ws = wb.active
count=0
while count < (ws.max_column):
    for row in ws.rows:
        if row[count].value == "CCL":
            print(row)
    count+=1

The output will be the tulpe of indexes.

(<Cell 'Results'.A10>, <Cell 'Results'.B10>, <Cell 'Results'.C10>, <Cell 'Results'.D10>)

You can parse the exact indexes from tuple if you want!!!