VBA Excel错误13类型不匹配

Question

I have the next code that validate ID into 2 worksheets, it works okay but every time I run the macro I get the Mismatch error and I do not know what I am doing wrong or I do not know if I am missing something, I have checked all the answers before to come here but still nothing.

The error occurs at Set j = .Range("A:A").find(findValue)

This is my code:

Sub Save_comments()
Dim i As Integer
Dim j As Range

k = Sheets("List").Cells(Rows.Count, "P").End(xlUp).Row
For i = 1 To k
    findValue = Sheets("List").Cells(i, 16).Value
    With Sheets("Historical_Data")
        l = .Cells(Rows.Count, "A").End(xlUp).Row + 1
        Set j = .Range("A:A").find(findValue) '<-- error here
        If Not j Is Nothing Then
            If Sheets("List").Cells(i, 18).Value <> "" Then
                .Cells(j.Row, j.Column).Offset(0, 2).Value = Sheets("List").Cells(i, 18).Value
            End If
        Else
            .Cells(l, 1).Value = Sheets("List").Cells(i, 16).Value
            .Cells(l, 3).Value = Sheets("List").Cells(i, 18).Value
        End If
    End With
Next i
End Sub

Answer 1

Try to modify your code as follows:

Sub Save_comments()
Dim i As Integer
Dim j As Range

k = Sheets("List").Cells(Rows.Count, "P").End(xlUp).Row
For i = 1 To k
    findValue = Sheets("List").Cells(i, 16).Value

    If Application.IsNA(findValue) = False Then

        With Sheets("Historical_Data")
            l = .Cells(Rows.Count, "A").End(xlUp).Row + 1
            Set j = .Range("A:A").Find(findValue) '<-- error here
            If Not j Is Nothing Then
                If Sheets("List").Cells(i, 18).Value <> "" Then
                    .Cells(j.Row, j.Column).Offset(0, 2).Value = Sheets("List").Cells(i, 18).Value
                End If
            Else
                .Cells(l, 1).Value = Sheets("List").Cells(i, 16).Value
                .Cells(l, 3).Value = Sheets("List").Cells(i, 18).Value
            End If
        End With

    End If
Next i
End Sub

The reason of your error is most probably N/A value assigned to findValue variable - this means that findValue variable has some error value. Here is the list of potential error numbers:

Answer 2

This is how a minimal version of your code looks like:

Sub SaveComments()

    Dim i           As Long
    Dim j           As Range
    Dim findValue   As String

    For i = 1 To 20
        findValue = Sheets("List").Cells(i, 16).Value
        With Sheets("Historical_Data")
            Set j = .Range("A:A").Find(findValue)    '<-- error here
            Debug.Print j.Address
        End With
    Next i    
End Sub

If it does not work, simply try to see what is the findValue in the case when it breaks.