按 id 数组过滤对象数组

Question

I have an array activeIds of ids of services and there is another array servicesList which contains objects of services.

Example: -

activeIds = [202, 204]
serviceList = [{  
                "id":201,
                "title":"a"
               },
               {  
                "id":202,
                "title":"a"
               },
               {  
                "id":203,
                "title":"c"
               },
               {  
                "id":204,
                "title":"d"
               },
               {  
                "id":205,
                "title":"e"
               }];

I want all the services(obj) whose ids are not a part of the first array ie, activeIds . From the above example code I want service obj of ids 201,203,205

Final output -

expectedArray = [{  
                "id":201,
                "title":"a"
               },
               {  
                "id":203,
                "title":"c"
               },
               {  
                "id":205,
                "title":"e"
               }];

Here is my attempt to code. But it is not correct at all. Please help-

    const activeIds = e; // [202, 204]
    const obj = [];
    this.serviceList.map((s: IService) => {
        activeIds.map((id: number) => {
            if (id !== s.id) {
                obj.push(s);
            }
        });
    });

Answer 1

You can simply use array.filter with indexOf to check the matching element in the next array.

var arr = serviceList.filter(item => activeIds.indexOf(item.id) === -1);

DEMO

 let activeIds = [202, 204] let serviceList = [{ "id":201, "title":"a" }, { "id":202, "title":"a" }, { "id":203, "title":"c" }, { "id":204, "title":"d" }, { "id":205, "title":"e" }]; let arr = serviceList.filter(function(item){ return activeIds.indexOf(item.id) === -1; }); console.log(arr);

Answer 2

You can do this with filter and includes methods.

 const activeIds = [202, 204] const serviceList = [{"id":201,"title":"a"},{"id":202,"title":"a"},{"id":203,"title":"c"},{"id":204,"title":"d"},{"id":205,"title":"e"}] const result = serviceList.filter(({id}) => !activeIds.includes(id)); console.log(result)

Answer 3

Use filter & indexOf method. indexOf will check if the current id is present in activeIds array

 var activeIds = [202, 204] var serviceList = [{ "id": 201, "title": "a" }, { "id": 202, "title": "a" }, { "id": 203, "title": "c" }, { "id": 204, "title": "d" }, { "id": 205, "title": "e" } ]; var filteredArray = serviceList.filter(function(item) { return activeIds.indexOf(item.id) === -1 }); console.log(filteredArray)

Answer 4

您可以结合indexOf来检查当前 id 是否在活动数组上并过滤数组。