如何使用Selenium Python xpath单击某些按钮？

Question

I am trying to scrap a web site News list after searching a certain word. But I can't figure out how to access News list.

First of all, I entered a key work and click search button.

elem = driver.find_element_by_id("query") 
elem.send_keys("kpop")    
elem = driver.find_element_by_id("search_btn")
elem.click()

The result page is this: https://search.naver.com/search.naver?sm=tab_hty.top&where=nexearch&query=kpop&oquery=kpop&tqi=To2nllpySEKsssnbxrsssssssFd-407861

And I want to move on News tab placed on third tab

Please help!

Answer 1

Right-click the desired element. Copy the xpath. Paste it in .find_element_by_xpath() .

button = driver.find_element_by_xpath('//*[@id="nx_search_form"]/fieldset/button ')

Answer 2

As per the url you have shared to click on the link to move on to the News tab placed on third tab you can use the following line of code :

driver.find_element_by_xpath("//ul[@class='base']/li[@class='lnb4']/a[@class='tab']/span[@class='spnew']").click()

You may require to induce WebDriverWait for the webelement to be clickable as follows :

WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//ul[@class='base']/li[@class='lnb4']/a[@class='tab']/span[@class='spnew']"))).click()