从文本文件中提取特定行

Question

I have a data in my .txt file as below, I want to extract the line that have value as 12 and copy it into new .txt file. I tried with sed but could get the result, any help would be appreciated . Thanks

"944760 1939"   10
"944760 1940"   12
"946120 1940"   2
"946370 1939"   10
"946370 1940"   12
"946460 1940"   6
"946530 1939"   10

Answer 1

Why don't just search forum, before posting here, so many posts repeated

awk '$3 == 12' infile > outfile

which is same as

awk '$3 == 12 { print }' infile > outfile 

Explanation

• $3 == 12 if 3rd column is equal to 12, print such record/row

Answer 2

Following simple awk may help you on same:

awk '$NF==12{print $0 > "new_file"}'   Input_file

Explanation:

$NF==12 : Checking condition here if last field's value is 12 means condition is TRUE then perform further/following statements.

{print $0 > "new_file"} : Printing current line($0) value to a output file named

new_file (you could change its name as per your wish too).

Input_file : Mentioning Input_file name here.

Solution 3rd: As per karafka sir's comment adding this one too now.

awk'$NF==12' Input_file > "new_file"