[英]Turn list of different length vectors into a `tibble`
I currently have a list of character vectors that are different lengths. 我目前有一个不同长度的字符向量列表。 Like this: 像这样:
list(
c('this','is','first'),
c('this','is','second','it','longer'),
c('this is a list','that is length 2')
)
I'd like to combine all the elements of each vector in the list into a single row in a tibble
. 我想在列表中的每个向量的所有元素组合成一个单一的行中的tibble
。 Like this: 像这样:
data_frame(column_1 =
c('this is first',
'this is second it longer',
'this is a list that is length 2'))
I'd like to use base R or packages from the tidyverse
if possible. 我想尽可能使用base R或tidyverse
软件包。
You can use purrr
and stringr
您可以使用purrr
和stringr
x <- list(
c('this','is','first'),
c('this','is','second','it','longer'),
c('this is a list','that is length 2')
)
tibble(column1= map_chr(x, str_flatten, " "))
Note that str_flatten
is new to stringr_1.3.0
请注意, str_flatten
是str_flatten
的新stringr_1.3.0
This could also be easily done with base R (no tidyverse functions) 使用基数R(没有tidyverse函数)也可以轻松完成此操作
data.frame(column1 = sapply(x, paste, collapse= " "))
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.