如何在节点中导入的js文件中获取当前路径

Question

I have 2 files A.js and B.js , they are structured as follows:

packgages
|
 – B
   |
    - B.js
A.js

In my A.js I simply do this:

import B.js

In my B.js I want to know the full path to this file ( B.js ):

console.log(__dirname);

So if I execute cd packages/B; node B.js cd packages/B; node B.js I get the following result:

/Users/luke/Projekte/writejs/code/verne/packages/B

But if I excecute node A.js I get this:

/Users/luke/Projekte/writejs/code/verne

See that the __dirname does not refer to the file from which is it called but to the file that executes it in its root.

Is there a way to get the full path to /packages/B no matter which file I am importing it from?

Answer 1

I have never worked with Rollup, but from what I can understand from the introduction on its page, its purpose is to transpile ES6 scripts into a single js file. So if have the following files:

moduleA.js

import p from "./myModules/moduleB";

console.log(__dirname);
console.log(__filename);

p();

myModules/moduleB.js

export default function () {
  console.log(__dirname);
  console.log(__filename);
}

When executing Rollup on moduleA.js

rollup -i moduleA.js -f cjs -o rollup.js 

I obtain the following file:

rollup.js

'use strict';

function p () {
  console.log(__dirname);
  console.log(__filename);
}

console.log(__dirname);
console.log(__filename);

p();

As you can see, any reference to the previous structure is gone. Also, everything is in one single file, so the directory would not change.

I have also tried to find a way to maintain the directory structure when creating Rollup bundle, but can't find any solution.