如何在 javascript 中为 ExtraFields 制作正则表达式
[英]How can i make regular expression for ExtraFields in javascript
问题描述
ExtraFields[milage_1][from] ExtraFields[milage_1][to] 
ExtraFields[milage_1][from] ExtraFields[milage_1][to]
ExtraFields[model_year_example_1998_2001_0][from]
ExtraFields[model_year_example_1998_2001_0][to]
This is the values i just want to check for Extrafields and [from] .这是我只想检查Extrafields and [from] 。
i.match(/^ExtraFields.*[f.*.m]/g)
but it pass through for both [from] and [to] and i want to only make true if there is [from] only.但它通过 [from] 和 [to] 并且我只想在只有 [from] 时才为真。
1 个解决方案
解决方案1
0 2018-02-26 10:32:50
我所做的是删除[f.*.m]括号这对我/^ExtraFields.*f.*.m/g
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