如何在Python 3中迭代浮点数？

Question

So now I have a variable which is x = 1001.0010101

From this x, I wanna separate into two parts:

x = 1001.0010101
val_int = int(x)                         #get val_int   = 1001
val_fract = {0:.5f}".format(a - val_int) #get val_fract = 0.00101

Is it possible to use for loop to iterate the val_fract to be like: (ignore the int part and decimal point)

0 
0 
1 
0 
1

I have tried so many times and I couldn't get it done and the system told me

Traceback (most recent call last):
  File "python", line 46, in <module>
TypeError: 'float' object is not iterable

Thanks for your help, much appreciated.

Answer 1

You can use math module in python to separate decimal and integer part

import math 
x = 1001.0010101
math.modf(x)
#output:(0.0010101000000304339, 1001.0)

Iterate as you want

Have doubt about extra numbers in end of decimal read docs

Answer 2

I don't know, why you suggest in your comment that leading zeros are missing:

x = 1001.0010101
#separate fractional from integer part
frac = str(x).split(".")

for digit in frac[1]:
    print(digit)

Alternatively, you can transform both parts into lists of integers:

#integer digits
x_int = list(map(int, frac[0]))
#fractional digits
x_frac = list(map(int, frac[1]))

Answer 3

x = 1001.0010101
x = "{0:.5f}".format(x)
for i in str(x).split(".")[1]:
    print(i)

Output :

0
0
1
0
1