遍历Python中的Float列表

Question

I am trying to iterate over a list of float values using for loop but getting the error. I am trying to print the list using enumerate(). Is there a better way to iterate over a list of floats?

The list has numbers like list_float= [1546626931.138813,1546626931.138954,1546626931.139053,1546626931.139289,.......,1546628078.463885]

Code is:

import csv
import datetime
import pandas


filename = open('C:\\Users\\xyz\\Downloads\\BLF File\\output.csv', "w")
log = can.BLFReader('C:\\Users\\xyz\\Downloads\\BLF File\\test.blf')

# print ("We are here!")
log_output = []
timestamp = [] #Variable to store timestamps from blf file
time_del = [] #Variable to store time difference
# filename.write('Timestamp              ID             DLC                 Channel' + '\n')

print('We are here 1')
for time in log:
    time = str(time).split()
    timestamp = float(time[1])
    # print(timestamp)


for count, item in enumerate(timestamp):
    print(count, item)

It is only printing the last float value in the list which is ' 1546628078.463885 ' as below:

0 1
1 5
2 4
3 6
4 6
5 2
6 8
7 0
8 7
9 8
10 .
11 4
12 6
13 3
14 8
15 8
16 5 

In the file I have passed the values are like below:

['Timestamp:', '1546626926.380693', 'ID:', '0366', 'S', 'DLC:', '8', '25', '80', 'f8', '7f', '00', '00', '00', '00', 'Channel:', '0']
['Timestamp:', '1546626926.381285', 'ID:', '0120', 'S', 'DLC:', '2', '00', '05', 'Channel:', '1']

Answer 1

This loop overwrites timestamp each time, so in the end timestamp is a single float rather than a list of floats.

for time in log:
    time = str(time).split()
    timestamp = float(time[1])

You probably want:

for time in log:
    time = str(time).split()
    timestamp.append(float(time[1]))