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Java循环如何通过跳转使增量?

[英]Java loops how to make incremental with jump?

Trying to make a loop in java that goes like this 试图在Java中进行这样的循环

1
2
3
4
5
1000
1010
1020
1030
1040

Right now my code is 现在我的代码是

 for(int j = 1; j <=5; j += 1){
     for(int i = 1000; i <=1040; i += 10){
         System.out.println(+ j );
         System.out.println(+ i );
     }
 }

And this is not working at all as its printing every number 5 times. 这根本不起作用,因为它每打印5次。

Two separate loops since there is no relation between first 5 and last 5 numbers. 由于前5个数字和后5个数字之间没有关系,因此有两个单独的循环。

for(int j = 1; j <=5; j += 1) {
    System.out.println(j);
}

for(int i = 1000; i <=1040; i += 10){
    System.out.println(i);
}

Please try this. 请尝试这个。 If your purpose is to only display the number like above. 如果您的目的只是显示上面的数字。 Then you can do that with one for statement. 然后,您可以使用一个for语句来做到这一点。

public class HelloWorld
{
  public static void main(String[] args)
  {
    for(int j = 1; j <=5; j += 1){
      System.out.println(j);
    }
    for(int i = 1000; i <=1040; i += 10){
        System.out.println(i);
    }
  }
}

Or if you really really really want to do it in one loop: 或者,如果您真的很想在一个循环中这样做:

int i=1;
while(i<=1040)
{
   System.out.println(i);
   if(i<5){i++; continue;}
   else if(i==5){i=1000; continue;}
   else i+=10; 
}

Output: 输出:

1
2
3
4
5
1000
1010
1020
1030
1040

Otherwise just use 2 for loops (the first with +1 increment, the second with +10 increments) in sequence and not nested. 否则,只需按顺序使用2 for循环(第一个循环以+1递增,第二个循环以+10递增)且不嵌套。

for(int j=1; j<=5; j++) {
    System.out.println(j);
}

for(int j=1000; j<=1040; j+=10){
    System.out.println(j);
}

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