替换列表回到python中的原始列表

Question

I have a list like below in python/pyspark like below. I want to convert the special characters in the list to something else.

I have done like below.

cols = ['abc test', 'test*abc', 'eng)test', 'abc_&test']

reps = [(' ', '_&'), ('(', '*_'), (')', '_*'), ('{', '#_'), ('}', '_#'), (';', '_##'), ('.', '_$'), (',', '_$$'), ('=', '_**')]

replacedCols = []
for col in cols:
    for x in reps:
        col = col.replace(x[0], x[1])
    replacedCols.append(col)

checkCols = replacedCols[:]
for index, col in enumerate(replacedCols):
    checkCols[index] = ''
    replacedCols[index]
    if col in checkCols:
        replacedCols[index] = col.replace('_', '__')

The new list is like below:

New_cols = ['abc__&test', 'test*abc', 'eng_*test', 'abc_&test']

Now I want to convert this list back to the original list:

new_cols = ['abc__&test', 'test*abc', 'eng_*test', 'abc_&test']

reps = (('_&', ' '), ('*_', '('), ('_*', ')'), ('#_', '{'), ('_#', '}'), ('_##', ';'), ('_$', '.'), ('_$$', ','), ('_**', '='))


replaced_ColsCols = []
for col in new_cols:
    for x in reps:
        col = col.replace(x[0], x[1])
    replaced_Cols.append(col)

check_Cols = replaced_Cols[:]
for index, col in enumerate(replaced_Cols):
    check_Cols[index] = ''
    replaced_Cols[index]
    if col in check_Cols:
        replaced_Cols[index] = col.replace('__', '_')

print(replaced_Cols)

I got the result like below which is not the same as the original list

old_cols = ['abc_ test', 'test*abc', 'eng)test', 'abc test']

What do I need to do to get the the desired result

Answer 1

I see that it is the continued post from this and you are trying to reverse the idea presented as answer in there .

In that post you had changed ['abc test', 'test*abc', 'eng)test', 'abc_&test'] to ['abc__&test', 'test*abc', 'eng_*test', 'abc_&test'] and you want to reverse the changes.

You don't have to reverse the changes as you already have the original list

But in case you want to learn new stuffs here's the working code for you

new_cols = ['abc__&test', 'test*abc', 'eng_*test', 'abc_&test']
reps = (('_&', ' '), ('*_', '('), ('_*', ')'), ('#_', '{'), ('_#', '}'), ('_##', ';'), ('_$', '.'), ('_$$', ','), ('_**', '='))

for index, col in enumerate(new_cols):
    if '__' in col:
        new_cols[index] = col.replace('__', "_")

replaced_ColsCols = []
checkCols = new_cols[:]
for col in new_cols:
    if new_cols.count(col) > 1:
        checkCols.remove(col)
    if col in checkCols:
        for x in reps:
            col = col.replace(x[0], x[1])
    replaced_ColsCols.append(col)

print replaced_ColsCols

which should give you

['abc test', 'test*abc', 'eng)test', 'abc_&test']