如何使Ocaml函数的参数成为可变的int？

Question

I want to make a function in which the parameter is mutable. I'm familiar with let a = ref 0 but how can i make "a" be a parameter for my function?

Answer 1

If you ask Ocaml nicely, it will infer the right type for you:

 let incr x =  x:= !x + 1

val incr : int ref -> unit = < fun >