使用正则表达式从字符串中提取数字

Question

I need to extract number from string 'iama5559348number'. Answer should do non capturing and expected output is 5559348. I am trying by doing this way print(re.search(r'([^(.*)]?[0-9]*)','iama5559348number')) but I am getting only only first letter

Answer 1

>>> print(re.search(r'([0-9]+)','iama5559348number').groups()[0])
'5559348'

or

>>> print(re.search(r'(\d+)','iama5559348number').groups()[0])
'5559348'

Answer 2

You can use re.findall that way:

x= re.findall(r'[0-9]+','iama5559348number')[0]
print(x)

or that:

x= re.findall(r'\d+','iama5559348number')[0]
print(x)