如何从两个特定单词之间的字符串中获取文本？

Question

I get the whole HTML code from JSON using Ajax , The fetched string looks like : 我使用Ajax从JSON获取了整个HTML代码，所提取的字符串如下所示：

<!DOCTYPE html>
 <html lang="en">
    <head>
        <meta charset="utf-8">
        <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">        
        <meta http-equiv="X-UA-Compatible" content="IE=edge">
        <meta name="viewport" content="width=device-width, initial-scale=1">         
        ..
    </head>
    <body>
        <div class="container">
            ...
        </div>
        <div id="overlay"></div>
        <script></script>
        ..
    </body>
</html>

I want to get the whole code from the div with class container <div class="container"> to this one <div id="overlay"></div> . 我想将整个代码从具有类容器<div class="container"> <div id="overlay"></div>到这一个<div id="overlay"></div> 。

How to accomplish that so that I just get the html part I want from the <body> not the whole string? 如何做到这一点，以便我只从<body>获得我想要的html部分而不是整个字符串？

Answer 1

<script>
    (function(window, document){ 
        // `res` is the ajax response string 
        const res = `<!DOCTYPE html> 
        <html lang="en"> 
        <head> 
        <meta charset="utf-8"> 
        <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> 
        <meta http-equiv="X-UA-Compatible" content="IE=edge"> 
        <meta name="viewport" content="width=device-width, initial-scale=1"> 
        </head> 
        <body> 
        <div class="container"> 
        stuff from container. 
        </div> 
        <div id="overlay"></div> 
        </body> 
        </html>`; 
        const wrapper = document.createElement("div"); 
        wrapper.innerHTML = res; 
        let str = ''; 
        str+=wrapper.querySelector("div.container").outerHTML; 
        str+=wrapper.querySelector("div#overlay").outerHTML; 
        alert(str); 
    })(window, document); 
</script>

如何从两个特定单词之间的字符串中获取文本？

问题描述

1 个解决方案

解决方案1
3 已采纳 2018-03-19 17:15:20

如何从两个特定单词之间的字符串中获取文本？

问题描述

1 个解决方案

解决方案1 3 已采纳 2018-03-19 17:15:20

解决方案1
3 已采纳 2018-03-19 17:15:20