从整个字符串JavaScript中提取两个单词之间的文本

Question

I have a string where I want to extract all the words that is between two text, such that:

var str="This is the number I want +2143334 !, again this is the next number I want +234343443 !, last number I want +76645 !, fininshed";

var ext = str.split('want').pop().split('!,').shift(); 
alert(ext);

But this gives only +2143334 . What I want is all three matching ie:

+2143334, +234343443, +76645

How can it be done?

Answer 1

You may use the following regex to capture the + followed with 1+ digits after want :

 /want\s*(\+\d+)/g

See the regex demo .

Here, want matches a literal substring, then \\s* matches 0+ whitespace chars and the (\\+\\d+) captures into Group 1 a plus sign and then 1+ digits.

In Chrome, you may even use str.match(/(?<=want\\s*)\\+\\d+/g) , but not all browsers already support the ECMAScript 2018 cool regex features.

JS demo:

 var str="This is the number I want +2143334 !, again this is the next number I want +234343443 !, last number I want +76645 !, fininshed"; var m,results = []; var rx = /want\\s*(\\+\\d+)/g; while(m=rx.exec(str)) { results.push(m[1]); } console.log(results); 

Answer 2

You can use the RegExp (?<=want )([^ ]*)(?= !) :

(?<=want ) makes sure want[space] is behind your expression

([^ ]*) matches anything but a space

(?= !) makes sure [space]! is after your expression

The g is added to make the RegEx global .

 var str = "This is the number I want +2143334 !, again this is the next number I want +234343443 !, last number I want +76645 !, fininshed"; console.log(str.match(/(?<=want )([^ ]*)(?= !)/g)); 

Answer 3

Actually your code is giving +76645 as result. Anyway, the more straigthforward way to do it is as follows:

 var str="This is the number I want +2143334 !, again this is the next number I want +234343443 !, last number I want +76645 !, fininshed"; // To extract numbers only var vetStrings = str.match(/\\d+/g); console.log(vetStrings); // To cast the result as numbers var vetNumbers = vetStrings.map(Number); console.log(vetNumbers); 

:)

Answer 4

My suggestion:

var reg = /(?<=want\s)[a-zA-Z0-9+]+(?=\s\!)/g;
var yourText = 'This is the number I want +2143334 !, again this is the next number I want +234343443 !, last number I want +76645 !, fininshed';
var resultArray = yourText.match(reg);
console.log(resultArray);

Where

want\\s

(\\s is for space) is text before your match, and

\\s\\!

if for text after your match.

Best regards ;)

Answer 5

你可以用这个

  str.match(/want\s[a-zA-Z0-9+!@#$%^&*()_+={}|\\]+\s!/g).map((e)=>e.split(' ')[1])