[英]How to do a numeric reverse sort in python on a list which contains numbers and letters
My list is like this: 我的清单是这样的:
10.987|first sentence
13.87|second sentence
9.098|third sentence
if I do something like: 如果我做类似的事情:
for x in my_list:
sorted(my_list, reverse=True)
I logically get: 我从逻辑上得到:
9.098|third sentence
13.87|second sentence
10.987|first sentence
This is because it is not interpreted as a number but I can't convert the whole string to a float. 这是因为它没有被解释为数字,但是我无法将整个字符串转换为浮点数。 What I want is a numeric sort of the first part:
我想要的是第一部分的数字排序:
13.87|second sentence
10.987|first sentence
9.098|third sentence
I tried using itemgetter but I can't seem to find exactly what I am looking for. 我尝试使用itemgetter,但似乎找不到我想要的东西。 In bash this can easily be solved with
在bash中可以轻松解决
sort -k
Is there an equivalente to do this in python? 在python中有等效的工具吗?
Here is one way. 这是一种方法。
lst = ['10.987|first sentence',
'13.87|second sentence',
'9.098|third sentence']
res = sorted(lst, key=lambda x: -float(x.split('|')[0]))
Result 结果
['13.87|second sentence',
'10.987|first sentence',
'9.098|third sentence']
Explanation 说明
sorted
takes an argument key
which allows you to specify a custom ( lambda
) function on which to sort. sorted
使用参数key
,可让您指定要进行排序的自定义( lambda
)函数。 lambda
function splits by "|" lambda
函数以“ |”分隔 and extracts the first part to get the numeric component. float
and finally negate to ensure descending order. float
并最终求反以确保降序。 reverse=True
argument may be used. reverse=True
参数。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.