SPARQL在两个谓词上的排名

Question

Is it possible to create a SPARQL query that produces a result with the ranking based on two predicates? I have searched for similar queries the closest solution I could find is given in this thread . That solution gave me a timeout since I have about 600 triples so an efficient solution will be greatly appreciated. Consider the RDF below:

@prefix : <http://example.org#> .

:A :groupid 119;
   :date 2018-04-01.
:B :groupid 119 ;
   :date 2018-03-01.
:C :groupid 119 ;
   :date 2018-05-01.
:D :groupid 120  ;
   :date 2018-02-01.
:E :groupid 120 ;  
   :date 2018-03-01. 

I would like to get the following result:

| id   |   date     |ranking  |
==============================
| 119  | 2018-03-01 | 1       |
| 119  | 2018-04-01 | 2       |
| 119  | 2018-05-01 | 3       |
| 120  | 2018-02-01 | 1       |
| 120  | 2018-03-01 | 2       |
--------------------------------

Answer 1

As answered by AKSW, this script works perfectly:

PREFIX : <http://example.org#> 
SELECT ?id ?date (COUNT(*) as ?ranking)
{
   ?x :groupid ?id ; :date ?date .
   ?y :groupid ?id ; :date ?date2 .
    filter(?date2 <= ?date) 
}
GROUP BY ?id ?date
ORDER BY ?id ?date ?ranking