C ++模板根据类型选择代码块

Question

Is it possible within a C++ template function to enable/disable a block of code at compile time , based on the type of a parameter?

(If it is possible, I suspect std::enable_if may be part of the solution, but I haven't yet seen how to select a code block at compile time based on that.)

I'm looking to do something like this.

template<typename T>
void captureData(T *data, size_t len, T scaleFactor)
{
    initCaptureDevice();

    for (size_t i = 0; i < len; i++)
    {
        IF(T is integral type) // determine at compile time which to use
        {
            data[i] = getRawSample();
        }
        ELSE
        {
            data[i] = getRawSample() * scaleFactor;
        }
    }

    cleanup();
}

Answer 1

This:

template<typename T>
void captureData(T *data, size_t len, T scaleFactor, int anotherParam)
{
    initCaptureDevice();

    for (size_t i = 0; i < len; i++)
    {
        if(std::is_integral<T>::value) // determine at compile time which to use
        {
            data[i] = getRawSample();
        }
        else
        {
            data[i] = getRawSample() * scaleFactor;
        }
    }
    cleanup();
}

will work just fine - compiler will remove code of not used branch of if(constexpr) ... else ...;