根据一列中的值从DataFrame中选择行

Question

DataFrame named "result"

**I am trying to get rows with the values == 0 from a DataFrame (named " result " that you see in the image attached). The SQL Query for something like this will be like: SELECT * FROM RESULT WHERE column_name equal to some_value My DataFrame has 2 columns. the 1st one is i think named ' Index ' and the 2nd one is named ' 0 ' (the names are by default -- didn't bother to change)

Because the 2nd column is a binary: based on whether the restaurant review (1st column) was positive or negative (1 or 0). I want to get only the rows (of the two columns based on the negative reviews). when I try the code: df.loc[df['column_name'].isin(some_values)] or in my case result.loc[result['0'].isin(0)]

I get the error: KeyError: '0'

Can anybody please help? **

Answer 1

If you want to select rows, whose value of column '0' is 0, it should be as simple as :

result[result[0] == 0]

However, as sacul has pointed out, you should check whether the name of your column is of type 'str' or 'int'.