根据另一个数据框中的值从DataFrame中选择行，并根据第二个DataFrame使用值更新其中一个列

Question

I have two Dataframes df and df1.

Main DataFrame is as follows:
DF:

    start   end price
0   A   Z   1
1   B   Y   2
2   C   X   3
3   A   Z   4
4   D   W   5

Second DataFrame:
DF1:

start   end price
    0   A   Z   100
    1   B   Y   200

I want the main dataframe df to update the values in 'price' columns based on the start and end in df1. it should update column value for all the rows having the same start and end as in df1. DF:

start   end price
0   A   Z   100
1   B   Y   200
2   C   X   3
3   A   Z   100
4   D   W   5

(all AZ and BY in df should get updated). Is there anyway I can get this output ? In reality the datframes have more columns but I want to update only one column(eg.'Price').

Answer 1

First, you can merge:

s = df1.merge(df2, left_on=['start', 'end'], right_on=['start', 'end'], how='left')

Then you can fillna and index your desired columns:

s.assign(price=s.price_y.fillna(s.price_x))[['start', 'end', 'price']]

  start end  price
0     A   Z  100.0
1     B   Y  200.0
2     C   X    3.0
3     A   Z  100.0
4     D   W    5.0

Answer 2

Using update

df=df.set_index(['start','end'])
df.update(df1.set_index(['start','end']))
df.reset_index()
Out[99]: 
  start end  price
0     A   Z  100.0
1     B   Y  200.0
2     C   X    3.0
3     A   Z  100.0
4     D   W    5.0

Answer 3

merge

df.drop('price', 1).merge(df1, 'left').fillna(df)

  start end  price
0     A   Z  100.0
1     B   Y  200.0
2     C   X    3.0
3     A   Z  100.0
4     D   W    5.0

---

1. I'm going to merge on ['start', 'end'] and that pesky price is going to get in my way. So, I drop it.
2. I need to preserve df index because I have that repeat of 'A' and 'Z' . So, I use a 'left' merge
3. Now my missing elements can be filled back in with df