将Base64图像插入数组PHP PDO

Question

I'm trying to insert Blob images retrieved from MySQL into an array using a while loop.

The database statement selected all images then i need to pass them all into an array.

So in theory, i should have an array of base64 encoded image corresponding to each record from my database.

Any help will be appreciated.

$sql = "SELECT img from artistlocation";

    try{
        $db = new db();
        $db = $db->connect(); 
        $stmt = $db->query($sql);
        $data = array();
        while($result = $stmt->fetch(PDO::FETCH_OBJ))

        {
            //$result = base64_encode(); ---- Something here im guessing
            $data[] = $result;
        }
       print_r ($data);
    }
    catch(PDOException $e){
        echo '{"error": {"text": '.$e->getMessage().'}';
    }

Answer 1

I see big issue i your code..

You use the same variable, $result , for fetching mysql row result and image content.

Second, you miss to encoding to base64 the file content.

Here is my solution:

$sql = "SELECT img from artistlocation";

try{
    $db = new db();
    $db = $db->connect(); 
    $stmt = $db->query($sql);
    $data = array();
    while($result = $stmt->fetch(PDO::FETCH_OBJ))

    {
        $data[] = base64_encode($result['img']);
    }
   print_r ($data);
}
catch(PDOException $e){
    echo '{"error": {"text": '.$e->getMessage().'}';
} 

Hope it will helps you.

Answer 2

So the answer to this question came from AbraCadaver.

 $sql = "SELECT img from artistlocation";

    try{
        $db = new db();
        $db = $db->connect(); 
        $stmt = $db->query($sql);
        $data = array();
        while($result = $stmt->fetch(PDO::FETCH_OBJ))    
        {
            $data[] = base64_encode($result->img);
        }

Thanks guys for the help!