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LazyInitializationException:无法初始化代理 - 否 Session

[英]LazyInitializationException: could not initialize proxy - no Session

I use spring-data-jpa with spring-boot(v2.0.0.RELEASE) , I just wrote a CRUD demo on MySQL, but an exception occurs during runtime, source code as follows:spring-data-jpa上使用了spring-boot(v2.0.0.RELEASE) ,刚刚在MySQL上写了一个CRUD demo,运行时出现异常,源码如下:

Source code源代码

User.java用户.java

@Entity
public class User implements Serializable {
    private static final long serialVersionUID = 1L;

    @Id
    private Integer id;
    private String username;
    private String password;

    ...getter&setter
} 

UserRepository.java UserRepository.java

public interface UserRepository extends JpaRepository<User, Integer> {

}

UserServiceTest.java UserServiceTest.java

@RunWith(SpringRunner.class)
@SpringBootTest
public class UserServiceTest {

    @Autowired
    private UserRepository userRepository;

    @Test
    public void getUserById() throws Exception{
        userRepository.getOne(1);
    }

}

application.yml应用.yml

spring:
  datasource:
    username: ***
    password: ***
    driver-class-name: com.mysql.jdbc.Driver
    url: ********
  thymeleaf:
    cache: false
  jpa:
    show-sql: true
    hibernate:
      ddl-auto: update

Exception details异常详情

org.hibernate.LazyInitializationException: could not initialize proxy - no Session

at org.hibernate.proxy.AbstractLazyInitializer.initialize(AbstractLazyInitializer.java:155)
at org.hibernate.proxy.AbstractLazyInitializer.getImplementation(AbstractLazyInitializer.java:268)
at org.hibernate.proxy.pojo.javassist.JavassistLazyInitializer.invoke(JavassistLazyInitializer.java:73)
at cn.shuaijunlan.sdnsecuritysystem.domain.po.User_$$_jvstc90_0.getUsername(User_$$_jvstc90_0.java)
at cn.shuaijunlan.sdnsecuritysystem.service.UserServiceTest.getUserById(UserServiceTest.java:33)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:498)
at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:50)
at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:12)
at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:47)
at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:17)

I try to another method userRepository.findOne(1) , it can run successfully.我尝试了另一种方法userRepository.findOne(1) ,它可以成功运行。

You can add @Transactional annotation to your test method to avoid this exception.您可以在测试方法中添加@Transactional注释以避免此异常。

Method getOne return the 'reference' (proxy) of the entity which properties can be lazy loaded.方法getOne返回可以延迟加载属性的实体的“引用”(代理)。 See it code - it uses getReference method of EntityManager .查看代码- 它使用EntityManager getReference方法。 From it javadoc:从它javadoc:

Get an instance, whose state may be lazily fetched.获取一个实例,其状态可能会被延迟获取。

In Spring the implementation of EntityManager is org.hibernate.internal.SessionImpl - so without the Session the Spring can not get this method.在 Spring 中EntityManager的实现是org.hibernate.internal.SessionImpl - 所以没有 Session Spring 无法获得这个方法。

To have a session you can just create a transaction...要进行会话,您只需创建一个事务...

Your test should be like this:你的测试应该是这样的:

@RunWith(SpringRunner.class)    


@SpringBootTest
@Transactional    

public class QuestionTesting {   

    @Test    
    public void test() {    

    }    
}    

just add in application properties spring.jpa.properties.hibernate.enable_lazy_load_no_trans=true只需添加应用程序属性 spring.jpa.properties.hibernate.enable_lazy_load_no_trans=true

In the service class please add a setter for entity manager by using the annoattion @PersistenceContext.在服务类中,请使用注解@PersistenceContext 为实体管理器添加一个setter。 To be specific, use具体来说,使用

 @PersistenceContext(type = PersistenceContextType.EXTENDED)

In this way, you can access lazy property.通过这种方式,您可以访问lazy 属性。

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