[英]LazyInitializationException - could not initialize proxy - no Session
I have a problem with LazyInitializationException and I don't know how to fix it. 我遇到了LazyInitializationException问题,而且我不知道如何解决它。
for (Long id : employeeIds)
{
List<ProjectEmployee> projectEmployeeList = projectEmployeeService.findProjectEmployeesWithinDates(id,
startDate, endDate);
// if no data, then continue with next employee
if (projectEmployeeList.isEmpty())
{
continue;
}
gridCreated = true;
Employee employee = projectEmployeeList.get(0).getEmployee();
Label titleLabel = new Label(employee.getPerson().getSurname() + " " + employee.getPerson().getName() + " ["
+ employee.getRole().getHumanizedRole() + "]");
titleLabel.setStyleName("header-bold");
ProjectEmployeePanel projectEmployeePanel = new ProjectEmployeePanel(id, startDate, endDate);
gridPanelsLayout.addComponents(titleLabel, projectEmployeePanel);
}
Before the problem was when I was calling .getperson=null but I fix the call findProjectEmployeesWithinDates asking there to get the person. 问题出在我打电话给.getperson = null时,但我修复了findProjectEmployeesWithinDates呼叫,要求在那里找人。 But then I got the exception when I call the 'findProjectEmployeesWithinDates'.
但是当我调用'findProjectEmployeesWithinDates'时,出现了异常。 The code findProjectEmployeesWithinDates:
代码findProjectEmployeesWithinDates:
public List<ProjectEmployee> findProjectEmployeesWithinDates(Long employeeId, LocalDate startDate, LocalDate endDate) {
List<Long> list = new ArrayList<>();
list.add(employeeId);
List<ProjectEmployee> listProjectEmployees = projectEmployeeRepository.findProjectEmployeesWithinDates(list,
LocaleUtils.getDateFromLocalDate(startDate, LocaleUtils.APPLICATION_DEFAULT_ZONE_ID),
LocaleUtils.getDateFromLocalDate(endDate, LocaleUtils.APPLICATION_DEFAULT_ZONE_ID));
for (ProjectEmployee pe : listProjectEmployees)
{
Hibernate.initialize(pe.getEmployee());
Hibernate.initialize(pe.getEmployee().getPerson());
}
return listProjectEmployees;
}
So using debbug i saw that : 因此,使用debbug我看到了:
Hibernate.initialize(pe.getEmployee()); ----line 105
Hibernate.initialize(pe.getEmployee().getPerson()); ---line 106
it goes at the first line here at the for loop in the findProjectEmployeesWithinDates but not at the second, and this is where the exception happens. 它在findProjectEmployeesWithinDates中的for循环的第一行,但不在第二行,这是发生异常的地方。
the error I get 我得到的错误
Caused by: org.hibernate.LazyInitializationException: could not initialize proxy - no Session
at org.hibernate.proxy.AbstractLazyInitializer.initialize(AbstractLazyInitializer.java:165) ~[hibernate-core-4.3.6.Final.jar:4.3.6.Final] at org.hibernate.Hibernate.initialize(Hibernate.java:75) ~[hibernate-core-4.3.6.Final.jar:4.3.6.Final] at com.xitee.ccpt.service.ProjectEmployeeService.findProjectEmployeesWithinDates(ProjectEmployeeService.java:105) ~[classes/:na] at com.xitee.ccpt.service.ProjectEmployeeService$$FastClassBySpringCGLIB$$63bfc6f9.invoke() ~[spring-core-4.1.1.RELEASE.jar:na] 在org.hibernate.proxy.AbstractLazyInitializer.initialize(AbstractLazyInitializer.java:165)〜[hibernate-core-4.3.6.Final.jar:4.3.6.Final]在org.hibernate.Hibernate.initialize(Hibernate.java: 75)com.xitee.ccpt.service.ProjectEmployeeService.findProjectEmployeesWithinDates(ProjectEmployeeService.java:105)的[hibernate-core-4.3.6.Final.jar:4.3.6.Final]〜com的[classes /:na] .xitee.ccpt.service.ProjectEmployeeService $$ FastClassBySpringCGLIB $$ 63bfc6f9.invoke()〜[spring-core-4.1.1.RELEASE.jar:na]
Project Employee class: 项目员工类别:
@Entity
@Table(name = "employee", schema = "ccpt_data") @NamedQuery(name = "Employee.findAll", query = "SELECT e FROM Employee e") public class Employee implements Serializable { private static final long serialVersionUID = 1L; @Table(name =“ employee”,schema =“ ccpt_data”)@NamedQuery(name =“ Employee.findAll”,query =“ SELECT e FROM Employee e”)公共类Employee实现Serializable {private static final long serialVersionUID = 1L;
@Id
@Column(name = "employee_id")
@SequenceGenerator(name = "EMPLOYEE_ID_GENERATOR", sequenceName = "employee_id_seq", allocationSize = 1)
@GeneratedValue(strategy = GenerationType.AUTO, generator = "EMPLOYEE_ID_GENERATOR")
private Long employeeId;
@OneToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "person_id")
private Person person;
@Column(name = "monthly_cost")
private String monthlyCost;
@Enumerated(EnumType.STRING)
@Column(name = "role")
private EmployeeRole role;
@Column(name = "employee_manager")
private String employeeManager;
@Column(name = "obsolete")
private Boolean obsolete;
@Column(name = "bank_account_number")
private String bankAccountNumber;
@Column(name = "last_employer")
private String lastEmployer;
@Column(name = "starting_day")
private String startingDay;
@Column(name = "hours")
private Short hours;
@OneToMany(mappedBy = "employee", cascade =
{
CascadeType.ALL
}, orphanRemoval = true)
private Set<EmployeeWorkload> employeeWorkloads;
@OneToMany(mappedBy = "employee", fetch = FetchType.LAZY, orphanRemoval = true)
private Set<ProjectEmployee> projectEmployee;
@OneToMany(mappedBy = "employee", cascade =
{
CascadeType.PERSIST
}, orphanRemoval = true)
private Set<Qualification> qualifications;
@OneToMany(mappedBy = "employee", cascade =
{
CascadeType.PERSIST
}, orphanRemoval = true)
private List<CareerExperience> careerExperiences;
@Transient
private Map<Integer, String> exportOptions;
@OneToMany(mappedBy = "employee", fetch = FetchType.LAZY, orphanRemoval = true)
private Set<ProjectEmployeeRejection> projectEmployeeRejections;
@Transient
private boolean decrypted = true; // allows editing and viewing for users with no encryption rights
/**
* Initialization vector used for encryption of this employee or NO_KEY if no encryption was used
*
* @since 0.4.0
*/
@Column(name = "iv")
private String iv;
@Column(name = "cis_employee_id")
private Long cISEmployeeId;
@Column(name = "experience_summary")
private String experienceSummary;
@Enumerated(EnumType.STRING)
@Column(name = "employee_job_type")
private EmployeeJobType employeeJobType;
@Column(name = "ending_day")
@Type(type = "date")
private Date endingDay;
@Column(name = "main_skill")
private String mainSkill;
public Employee()
{
}
public Long getEmployeeId()
{
return employeeId;
}
public void setEmployeeId(Long employeeId)
{
this.employeeId = employeeId;
}
public Person getPerson()
{
return person;
}
public void setPerson(Person person)
{
this.person = person;
}
public String getExperienceSummary()
{
return experienceSummary;
}
public void setExperienceSummary(String experienceSummary)
{
this.experienceSummary = experienceSummary;
}
Can anyone help me with this problem, please? 有人可以帮我解决这个问题吗?
I would recommend one of the following approaches: 我建议使用以下方法之一:
1) In you repository method findProjectEmployeesWithinDates
you can do 1)在您的存储库方法
findProjectEmployeesWithinDates
您可以执行
for (ProjectEmployee pe : listProjectEmployees)
{
pe.getEmployee().getPerson();
}
so it will initialize objects while session is open 因此它将在会话打开时初始化对象
2) You can fetch data using query 2)您可以使用查询获取数据
SELECT * FROM ProjectEmployee pe JOIN FETCH pe.employee e JOIN FETCH e.person
In this way Hibernates will populate execution result with employee and person objects automatically 这样,Hibernates将自动用员工和人员对象填充执行结果
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