[Unix] [Shell脚本]将所有文件从一个文件夹复制到另一个文件夹

Question

I am trying to create a bash shell script for daily cronjob.

The script is to copy all files with txt extension (including the sub-directories) from the folder "fromDir" to the folder "toDir".

It will also make the "toDir" directory if it doesnt exist.

I am trying to use tar here to compress the files and decompress after it moved to speed up the time it spent during the transfer, the target folder should have exactly the same structure as the original one.

#!/bin/bash -l

fromDir='c:/fromFolder/' ;
toDir='c:/toFolder/' ;
find $fromDir -maxdepth 3 -name '*.txt' -print |
tar zcvf - -T - |
mkdir -p -m 777 $toDir ;
cd $toDir && tar zxvf -

Answer 1

1st see my comment, then if you tar don't support -C argument (change to dir befor tar), you could try this:

#!/bin/bash

fromDir='c:/fromFolder/' ;
toDir='c:/toFolder/' ;
mkdir -p -m 777 $toDir ;
find $fromDir -maxdepth 3 -name '*.txt' -print |
tar zcf - -T - | (
    cd $toDir
    tar zxvf -
)

Answer 2

In case you could use rsync you could try this:

rsync -av --include="*/" --include="*.txt" --exclude="*" ~/from/ ~/to/ --dry-run

This can be interpreted as for include every directory with *.txt and exclude anything else (the order is important)

The option --dry-run is just to print what will be done but no files will be copied.