复制shell脚本中除一个文件以外的所有文件

Question

I am new to shell scripting.

I have a command which copies all tml/xml files in the current directly to another as below:

cp -f *.[tx]ml $path

But I need to exclude one file (excludeme.xml) while executing the above command.
I tried the below command but did not work.

find . -name "excludeme.xml" | xargs -0 -I {} cp -f *.[tx]ml $path

Answer 1

Try:

find . ! -name excludeme.xml | ...

or

ls *.[tx]ml | while read -r file; do 
    test x"$file" = xexcludeme.xml || cp -f "$file" "$path"
done

Note the leading 'x'; it is probably not necessary in modern shells, but will prevent errors when the file name begins with '-'.

Answer 2

If this is bash then

shopt -s extglob
cp !(excludeme).[tx]ml destination 

Answer 3

ls *.[tx]ml | grep -v excludeme.xml | xargs cp -f -t $path