php：如何获取数组的倒数第二个元素？

Question

There is an array, the count of the element is unknown,like this:

$arr=['a','m','q','y',....'b','f','n','s'];

How to get the second-to-last element in PHP ?

Answer 1

You can use array_slice() like this:

<?php
$arr=['a','m','q','y','b','f','n','s'];

echo array_slice($arr, -2, 1)[0];

Output:

n

Note: this will work regardless of the array type: indexed or associative. So even if the keys are not 0, 1, 2, 3, etc... then this would still work.

Answer 2

由于没有定义的键，因此更容易：

$second_to_last = $arr[count($arr) - 3];

Answer 3

我认为这就是答案;

$arr[count($arr)-3]