从python中的两个列表创建特定对

Question

I am currently trying to create specific pairs from two python lists:

Input:
l1 = ["fc1", "fc2"]
l2 = ["fh1", "fh2"]

Expected output:

outl1 = [["fc1","fh1"],["fc2","fh2"]]
outl2 = [["fc2","fh1"],["fc1","fh2"]]

You'll have guessed from this example that a "fc*" must be matched with a "fh*" and that any occurance of the list cannot be repeated in the final output.

I must admit I am quite confused by all the documentation if found online about zip, enumerate, itertools etc...

Thanks a lot in advance for your help.

Answer 1

You can use zip method by passing the both given lists as arguments.

For achieving the outl2 list you should use zip method which accepts two arguments : the l1 list, but reversed and l2 list.

zip method makes an iterator that aggregates elements from each of the iterables .

With the other words, zip returns an iterator of tuples , where the i-th tuple contains the i-th element from each of the argument sequences or iterables .

l1 = ["fc1", "fc2"]
l2 = ["fh1", "fh2"]

print([[a,b] for a,b in zip(l1,l2)])
print([[a,b] for a,b in zip(reversed(l1),l2)])

Output

[['fc1', 'fh1'], ['fc2', 'fh2']]
[['fc2', 'fh1'], ['fc1', 'fh2']]

Answer 2

If I understand you correct, you want to create all possible lists of pairs ('fci', 'fhj'), such that in each list all the 'fci' appear only once and the same for 'fhj'.

You can use itertools.permuations to achieve this. I generalized your example to include 3 elements per list.

from itertools import permutations 

A = ["fc1", "fc2", "fc3"]
B = ["fh1", "fh2", "fh3"]

B_permuations = permutations(B)

for perm in B_permuations:
    print([[a, b] for a, b in zip(A, perm)])

This will give you ​

[['fc1', 'fh1'], ['fc2', 'fh2'], ['fc3', 'fh3']]
[['fc1', 'fh1'], ['fc2', 'fh3'], ['fc3', 'fh2']]
[['fc1', 'fh2'], ['fc2', 'fh1'], ['fc3', 'fh3']]
[['fc1', 'fh2'], ['fc2', 'fh3'], ['fc3', 'fh1']]
[['fc1', 'fh3'], ['fc2', 'fh1'], ['fc3', 'fh2']]
[['fc1', 'fh3'], ['fc2', 'fh2'], ['fc3', 'fh1']]

Answer 3

if enumerate , zip and such is overwhelming at first use a simple for loops

l1 = ["fc1", "fc2"]
l2 = ["fh1", "fh2"]

a = []
for i1 in l1:
    a.append([[i1,i2] for i2 in l2])

for i in a:
    print(i)

output

[['fc1', 'fh1'], ['fc1', 'fh2']]
[['fc2', 'fh1'], ['fc2', 'fh2']]