如何使用与特定数字不匹配的对创建两个随机列表？

Question

I have 2 lists of random numbers that range from 0-7 that I want to pair up

listA = random.sample(range(8), 8)
listB = random.sample(range(8), 8)

However, I want to make sure that the number 1 in listA never pairs with itself or the number 4 from listB.

for a,b in zip (listA, listB):
  if a==b:
    random.shuffle(giver)
  if a==1 and b==4:
    random.shuffle(giver)

How do I ensure that both of those conditions are true for my lists?

Thank you for your time!

Answer 1

I came up with this:

import itertools
import random

list_a = random.sample(range(8), 8)
list_b = random.sample(range(8), 8)
it1 = itertools.cycle(list_a)
it2 = itertools.cycle(list_b)


def gen_pairs():
    count = 0
    while count < 8:
        x, y = next(it1), next(it2)
        if y == list_a[1] or x == list_b[4]:
            continue

        yield x, y
        count += 1


print(list_a[1])
print(list_b[4])

for _ in range(20):
    res = list(gen_pairs())
    assert (list_a[1], list_a[1]) not in res
    assert (list_b[4], list_b[4]) not in res

Answer 2

I hope I understood correctly and that this is of help:

import random

listA = random.sample(range(8), 8)
listB = random.sample(range(8), 8)

## This first search is just for listA[0]
zipped_list = []
good_match = False
while good_match == False:
    candidate = random.choice(listB)
    if listA[0] != candidate and listA[0] != listB[3]:
        zipped_list.append([listA[0], candidate])
        good_match = True

## Now we find numbers to match with the rest of listA
for num in listA[1:]:
    good_match = False
    while (good_match == False):
        candidate = random.choice(listB)
        if num != candidate:
            zipped_list.append([num, candidate])
            good_match = True
            
print(zipped_list)

Input example:

listA: [7, 4, 2, 1, 3, 0, 5, 6]
listB: [0, 3, 5, 1, 4, 2, 7, 6]

Output example: First element of listA (7) does not match with listB[0] or listB[4], and other numbers have not matched with themselves.

[[7, 1], [4, 1], [2, 6], [1, 0], [3, 2], [0, 2], [5, 2], [6, 2]]