快速排序中的gwt延迟计时器

Question

I'm writing a quick sort algorithm in GWT, between each iteration I'm trying to print the current status.

This is the method

private int partition(int[] list_of_numbers, int first, int last) {

        int pivot = list_of_numbers[first];
        int up = first;
        int down = last;

        do {
            while ((up < last) && pivot >= list_of_numbers[up]) {
                up++;
            }
            while (pivot < list_of_numbers[down]) {
                down--;
            }
            if (up < down) {
                swap(list_of_numbers, up, down);
                sortedResult.setText( array_to_string(list_of_numbers));
                logger.log(Level.SEVERE, sortedResult.getText());

            }
        } while (up < down);
        swap(list_of_numbers, first, down);
        sortedResult.setText( array_to_string(list_of_numbers));

        logger.log(Level.SEVERE, sortedResult.getText());
        return down;
    }

It works really well and we can see from the logger that it puts out the following

30, 3, 23, 7, 77, 46, 62, 91, 89, 22, 48, 96, 32, 40, 95, 
30, 3, 23, 7, 22, 46, 62, 91, 89, 77, 48, 96, 32, 40, 95, 
22, 3, 23, 7, 30, 46, 62, 91, 89, 77, 48, 96, 32, 40, 95, 
22, 3, 7, 23, 30, 46, 62, 91, 89, 77, 48, 96, 32, 40, 95, 
7, 3, 22, 23, 30, 46, 62, 91, 89, 77, 48, 96, 32, 40, 95, 
3, 7, 22, 23, 30, 46, 62, 91, 89, 77, 48, 96, 32, 40, 95, 
3, 7, 22, 23, 30, 46, 40, 91, 89, 77, 48, 96, 32, 62, 95, 
3, 7, 22, 23, 30, 46, 40, 32, 89, 77, 48, 96, 91, 62, 95, 
3, 7, 22, 23, 30, 32, 40, 46, 89, 77, 48, 96, 91, 62, 95, 
3, 7, 22, 23, 30, 32, 40, 46, 89, 77, 48, 96, 91, 62, 95, 
3, 7, 22, 23, 30, 32, 40, 46, 89, 77, 48, 62, 91, 96, 95, 
3, 7, 22, 23, 30, 32, 40, 46, 62, 77, 48, 89, 91, 96, 95, 
3, 7, 22, 23, 30, 32, 40, 46, 62, 48, 77, 89, 91, 96, 95, 
3, 7, 22, 23, 30, 32, 40, 46, 48, 62, 77, 89, 91, 96, 95, 
3, 7, 22, 23, 30, 32, 40, 46, 48, 62, 77, 89, 91, 96, 95, 
3, 7, 22, 23, 30, 32, 40, 46, 48, 62, 77, 89, 91, 95, 96, 

but on the output to the screen it will only display the last iteration

I would like to put a delay of 1 second after each sort where the user can see the current array.

I'm not sure how to use the timer in this case. As well I don't know if it is changing the value each time so fast that I only see the last one or if it's only changing it at the end.

Answer 1

A quick google search yields a page guiding you through delaying calculations and updating the interface.

You can find it here .