使用Python从文本中打印一些所需的行

Question

I would like to print out the lines that are in bold. I tried using .find() to match with the string "X-Sieve" so that the loop would revolve only before it matches with the text, but it doesn't seem to work. How can I do it?

Answer 1

Disclaimer:

First of all, What is your current output? 'Not working' is not enough for us to understand. Second, try to use real code in your questions rather than images - people don't necessarily want to manually copy your code to test.

Answer:

In case your code prints all lines in the moment, just add the following before the print statement at the bottom of your code:

if 'X-Sieve' in hand:
   break
else:
   print hand

Answer 2

I'm not too sure what you're going for here.
Like sudonym said, please paste your code, your text file and your output.

If those are the first few lines of the file, and it's always going to use those lines, you could apply this barebones script:

 #open foo.txt and assign it the var file1 file1 = open("foo.txt", "r") #read all the lines in the document, assigning the lines variable here lines = file1.readlines() #Printing the first 3 lines, remember python starts at 0 print(lines[0]) print(lines[1]) print(lines[2]) #close the file from memory file1.close() 

Foo.txt has the following data:

asdf theline2 welcometohell what up

The python script outputs the following:

asdf theline2 welcometohell