如何在Python中连续输出多行文本（一个接一个）

Question

So if I got for example:

print("some text\n
    some more text\n
    yet some more text")

and:

print("another some text\n
    another some more text\n
    yet another some more text")

How can print them next to each other without doing this:

print("some text         another some text\n
    some more text       another some more text\n
    yet some more text   yet another some more text")

I don't want to do what I just showed you, because I'll be generating more of this columns with different text and values, but I want them next to each other with the \\n breaks.

How can I do that in Python?

Answer 1

A simple way to go on about this is to loop over the lists of strings like so :

column_1 = ["some text", "some more text", "yet some more text"]
column_2 = ["another some text", "another some more text", "yet another some more text"]

for i in range(0, len(column_1 )):
    print("{}\t{}".format(column_1[i], column_2[i]))

If the length of both columns is the same of course. You could be more crafty with the tabbing if you want to align them better.

Answer 2

string1 = 'this is a\n string with\n line breaks'
string2 = ' beautiful\n some\n end'

stringcombined = ''.join(list(sum(list(zip(string1.split('\n'), ['\t'+i+'\n' for i in string2.split('\n')])), ()))).replace('\n ','\n')

print(stringcombined)

Output:

this is a     beautiful
string with   some
line breaks   end

Edit:

stringcombined = ''.join(list(sum(list(zip([i+'\n' for i in string1.split('\n')], [i+'\n' for i in string2.split('\n')])), ()))).replace('\n ','\n')

Output:

this is a
beautiful
string with
some
line breaks
end

Edit2:

For a third column just add it inside zip

string3 = '#\n#\n#'
stringcombined = ''.join(list(sum(list(zip([i+'\n' for i in string1.split('\n')], [i+'\n' for i in string2.split('\n')], [i+'\n' for i in string3.split('\n')])), ()))).replace('\n ','\n')

Output:

this is a
beautiful
#
string with
some
#
line breaks
end
#

Answer 3

Take a look into this example:

a = ["some text", 'some more text', 'yet some more text']
b = ["another some text", "another some more text", "yet another some more text"]
c = ["third text 1", "third text 2", "third text 3"]

print('\n'.join(a))
print('\n'.join(b))

# COMBINED MAGIC:
print('\n'.join(map(lambda x: ('{:30}'*len(x)).format(*x).strip(), zip(a, b, c))))

First two prints are equal to yours. As for the last one step-by-step:

1. zip N ( in this case N = 3 ) lists with strings into single one where each element is a tuple of corresponding elements from a , b , c lists
2. For each tuple we create formatter template using the lenght of each tuple.
3. Pass unpacked tuple to format function
4. Join with newline symbol
5. Print

Output from the last print call:

some text                     another some text             third text 1
some more text                another some more text        third text 2
yet some more text            yet another some more text    third text 3