格式化与其他变量串联的列表的打印

Question

I have a list data and its mean , median and mode as below:

data = [2, 3, 5, 5, 7, -6, -6, 9]
mean = 2.00
median = 3.00
mode = [5, -6]

I want to have a neat Pythonic output of the results. Using the answers recommended here and here I have come up with the following code.

print('Mean:{0:9.2f}\nMedian:{1:7.2f}'.format(mean, median),
  ''.join('\nMode: {}: {}'.format(*k) for k in enumerate(mode)))

However, I'm not confident if this is a good solution anyway and my output looks like this:

Mean:     2.38
Median:   4.00 
Mode: 0: -6
Mode: 1: 5

I want an output like:

Mean:     2.38
Median:   4.00
Mode:     -6, 5

Answer 1

I would just use tabs:

print('Mean:\t{}\nMedian:\t{}\nMode:\t{}'.format(mean,median,', '.join(str(i) for i in mode)))

giving:

Mean:   2.0
Median: 3.0
Mode:   5, -6

Answer 2

Use str.ljust() to make sure your titles (eg Mean , Median ) have a fixed length:

TITLE_LENGTH = 10
print("Mean:".ljust(TITLE_LENGTH) + "{:.2f}".format(mean))
print("Median:".ljust(TITLE_LENGTH) + "{:.2f}".format(median))
print("Mode:".ljust(TITLE_LENGTH) + "{}: {}".format(mode[0], mode[1]))

Output:

Mean:     2.00
Median:   3.00
Mode:     5: -6

Answer 3

format() can still be used as follows:

data = [2, 3, 5, 5, 7, -6, -6, 9]
mean = 2.00
median = 3.00
mode = [5, -6]

print('Mean:   {:.2f}\nMedian: {:.2f}\nMode:   {}'.format(mean, median, ', '.join(map(str, mode))))

Giving you:

Mean:   2.00
Median: 3.00
Mode:   5, -6