用不同的值更新一个数据库表列

Question

I want to update table with max three value and minimum with two values.How it would be possible to update table. I Get values from form, there are three fields for three students. Now all of them having same value when i update them in the database. Now i am trying this why. Dont know it works or not See my page

$s1_name=$_POST['s1_name'];
$s2_name=$_POST['s2_name'];
$s3_name=$_POST['s3_name'];

$query="update students SET Name=:Name
WHERE ProjectID='$id'
";

try
{

 $stmt = $conn->prepare( $query );  
 $stmt->bindParam(':Name', $s1_name);
 $stmt->bindParam(':Name', $s2_name);
 $stmt->bindParam(':Name', $s3_name);
 $result = $stmt->execute();
 $msg = "Record updated";
 }

 catch(PDOException $ex)
 {
  $msg = $ex -> getMessage();
 }

 } 

Answer 1

It does not work this way. The way you are doing it will result in the query only updating it for $s3_name .

You will have to do your try/catch statement for each query:

<?php

$names = [$_POST['s1_name'], $_POST['s2_name'], $_POST['s3_name']];
$query = "update students SET Name=:Name WHERE ProjectID='$id'";


foreach ($names as $name) {
    try
    {
        $stmt = $conn->prepare($query);  
        $stmt->bindParam(':Name', $name);
        $result = $stmt->execute();
        $msg = "Record updated";
    }
    catch(PDOException $ex)
    {  
       $msg = $ex -> getMessage();
    }
}