[英]R timezone GMT and CET convert unix timestamp
I got a unix timestamp from a GMT-based database wich i want to convert to datetime format. 我从基于GMT的数据库中获得了unix时间戳,我想将其转换为日期时间格式。 I use R in Germany.
我在德国使用R。 Unix timestamp from GMT-based database: 1525732148
来自基于GMT的数据库的Unix时间戳:1525732148
I convert it with: 我将其转换为:
install.packages("anytime")
library(anytime)
anytime(as.numeric(as.character(1525732148)))
Why do i get same date time, independet of system-date? 为什么我得到相同的日期时间,与系统日期无关?
anytime(as.numeric(as.character(1525732148, tz="GMT")))
anytime(as.numeric(as.character(1525732148, tz="CET")))
Both give me as result: "2018-05-07 22:29:08 UTC" 两者都给我结果:“ 2018-05-07 22:29:08 UTC”
I expected different results, because of different timezones. 由于时区不同,我预期会有不同的结果。
The problem is as follows: 问题如下:
> as.character(1525732148, tz="GMT")
[1] "1525732148"
This is what anytime
gets as input. 这就是
anytime
获得的输入。 The tz
parameter is supposed to be passed to anytime
, not to as.character
, which swallows without warning any additional parameters it does not recognise. tz
参数应该被传递给anytime
,而不是as.character
,它会吞咽而不会警告它无法识别的任何其他参数。 Try anytime(1525732148, tz="GMT")
. anytime(1525732148, tz="GMT")
尝试anytime(1525732148, tz="GMT")
。
> anytime::anytime(1525732148, tz="GMT")
[1] "2018-05-07 22:29:08 GMT"
> anytime::anytime(1525732148, tz="CET")
[1] "2018-05-08 00:29:08 CEST"
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