暂停 python 脚本等待按键

Question

I have a relatively simple script and a potentially simple question. Around the inte.net I've gathered a few solutions on how to use direct key press' as input in my python code. I'd prefer these to raw_input as it feels faster. Like if I have a menu with 3 options, and 3 options in each of those, I can easily press 3 then 2 on my keyboard to get where I need to go.

The code is:

import keyboard
import time

def mainmenu():
    while(True):
        print ('1. Scan')
        print ('2. Ping')
        print ('3. Exit')

        if keyboard.is_pressed('1'):
            print ('Option 1\n')
        elif keyboard.is_pressed('2'):
            print ('Option 2\n')
        elif keyboard.is_pressed('3'):
            print ('Exiting\n')
            exit(0)
        else:
            print ('none of the specified options were chosen')
            time.sleep(0.3)
            exit(0)
mainmenu()

I just want something that will pause the code where I can press a key.
I can't use time.sleep() for some reason. It doesn't like inputs in the split second before or after it either.
It would be awesome if I could get a function to do it so I could input it elsewhere along the way.

If I didn't have my else statement at the end, the while loop just keeps going.
If I don't have it in a while loop the script prints the options in 1 second and then defaults to else, because I haven't pressed a key in the 1 second.
I know it works because if I take out the else statement and while its spamming the options over and over I press 3, IDLE asks if I'd like to kill the script while its running.

Answer 1

You can use input() to have the same effect.

import time

def mainmenu():
    while(True):
        print ('1. Scan')
        print ('2. Ping')
        print ('3. Exit')

        x= input()
        if x==1:
            print ('Option 1\n')
        elif x==2:
            print ('Option 2\n')
        elif x==3:
            print ('Exiting\n')
            exit(0)
        else:
            print ('none of the specified options were chosen')
            time.sleep(0.3)
            exit(0)
mainmenu()

Answer 2

Use keyboard.read_key() as it will block the execution of the rest of code until a keyboard event happens, then returns that event's name or, if missing, its scan code.

import keyboard
import time

def mainmenu():
    print ('1. Scan')
    print ('2. Ping')
    print ('3. Exit')

    while(True):
        a = keyboard.read_key()

        if a == '1' or a == '2':
            print("Option {} was pressed\n".format(a))
        elif a == '3':
            print("Exiting\n")
            exit(0)
        else:
            print("None\n")
            exit(0)

        time.sleep(0.3)

mainmenu()

Answer 3

import time

def mainmenu(): while(True): print ('1. Scan') print ('2. Ping') print ('3. Exit')

    x=input()
    if x=='1':
        print ('Option 1\n')
    elif x=='2':
        print ('Option 2\n')
    elif x=='3':
        print ('Exiting\n')
        exit(0)
    else:
        print ('none of the specified options were chosen')
        time.sleep(1)
        

mainmenu()