Python：等待按键或直到超时

Question

I have a long-running Python script inside a terminal session (the host machine is a FreeBSD box) that performs a task every 9 minutes. Now, I'd like to be able to interrupt that sleep call at any moment so that it performs the task right away.

How can I do that? Catching Ctrl + C is not an option as I need it to stop the program (rather than merely interrupting the sleep). Anything else that I can do with a terminal window and a keyboard is fine.

Answer 1

With Thomas's suggestion, I came up with this function:

import signal

def input_or_timeout(timeout):
    def nothing(sig, frame): pass
    signal.signal(signal.SIGALRM, nothing)
    signal.alarm(timeout)
    try:
        raw_input()
        signal.alarm(0)
    except (IOError, EOFError): pass

It waits for input for at most timeout seconds.

Under Windows, I suppose you could replace raw_input() with getch() from msvcrt .