python findall（）返回空列表

Question

I want to use Python to get open API data. So, I parsed the URL to XML and tried to get the information I wanted through findall().

part of the data,

<safemap:CTPRVN_CD>11</safemap:CTPRVN_CD>
<safemap:SGG_CD>11500</safemap:SGG_CD>

i want this,

root.findall('safemap:ctprvn_cd')

but returned empty list.

Answer 1

XML is case-sensitive . I believe that root.findall('safemap:CTPRVN_CD') might work better.

Also I noticed that your xml seems to use namespaces . Usually there is a problem with namespaces, when working with xmls using lxml or xml package in python.