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如何声明从另一个方法的返回类型引用的变量/方法类型

[英]How to declare variable/method type referred from the return type of another method

One of my method returns a Class type. 我的方法之一返回Class类型。 I wanna use this Class type as the parameter/return type of another method like: 我想将此Class类型用作另一个方法的参数/返回类型,例如:

class A {
  def aClass: Class[_] = {
    if (...){
      classOf[String]
    }else{
      classOf[Int]
    }
  }
   //Neither works
  def kClass : aClass = {
    //...
  }
  def kClass : Class[aClass] = {
    //...
  }
}

It complains Cannot resolve symbol aClass . 它抱怨Cannot resolve symbol aClass

Can this type of metaprogramming be achieved in Scala at all? 可以在Scala中完全实现这种类型的元编程吗?

you can define a type like this and can use that type. 您可以定义这样的类型并可以使用该类型。 right now you are putting a def as a type and there is no type like aClass defined so it's giving you compile time error that aClass can't be resolved. 现在,您将def作为类型,并且没有像aClass这样定义的类型,因此它给您带来了无法解析aClass的编译时错误。 I think that should work for you. 我认为这应该为您工作。

final type aClass = Class[_]

      class A {
        def aClass: Class[_] = {
          if (true){
            classOf[String]
          }else{
            classOf[Int]
          }
        }

        //should works
        def kClass: aClass = {
          ...
        }
        def kClass1: aClass = {
          ...
        }
      }

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