在Scala中将CassandraRow转换为JSON形式的字符串

Question

I have this string:

CassandraRow{
    email: test@example.com,
    lastname: Example,
    name: User,
    password: Password}

How can I convert the above string in the form of JSON string of type?

{"email": "test@example.com",
 "lastname": "Example",
 "name": "User",
 "password": "Password"}

Answer 1

使用 dataAsString 方法提取 CassandraRow 中的任何内容，然后处理它就容易多了。