处理Javascript字符串中所有字母的出现

Question

Desired functionality:

var myString = "123a4 1b234";
console.log(myString.allInstancesOfLetter().something();
//"123A4 1B234"

Is there a way to do this without having to complicate things with an array of all 26 letters etc.?

edit: toUpperCase() causing confusion, I didn't really think of that interaction, I was just choosing a random function.

Answer 1

You can set a callback function as second parameter when using the replace method that will be applied to each ocurrence in a set RegExp.

 const myString = "123a4 1b234"; const result = myString.replace(/[az]/g, function(char) { return char.toUpperCase(); }); console.log(result); 

Answer 2

toUpperCase isnt applied to numbers, so

"123a4 1b234".toUpperCase()

works as expected.

Answer 3

You just need String.prototype.toUpperCase()

 var myString = "123a4 1b234"; console.log(myString.toUpperCase());