用LEFT连接连接值

Question

While searching, I came across a very similar post here but I have an additional question to what has been posted there already.

id|person_name|department_name|phone_number
--+-----------+---------------+------------
1 |"John"     |"Finance"      |"023451"
1 |"John"     |"Finance"      |"99478"
1 |"John"     |"Finance"      |"67890"
1 |"John"     |"Marketing"    |"023451"
1 |"John"     |"Marketing"    |"99478"
1 |"John"     |"Marketing"    |"67890"
2 |"Barbara"  |"Finance"      |""
3 |"Michelle" |""             |"005634"

Lets say I want the final result as:

id|person_name|department_name|phone_number
--+-----------+---------------+------------
1 |"John"     |"Finance"      |"023451", "99478", "67890"
1 |"John"     |"Marketing"    |"023451", "99478", "67890"
2 |"Barbara"  |"Finance"      |""
3 |"Michelle" |""             |"005634"

basically similar results from phone_number concatenated; then can you advise what should I be doing ? I tried GROUP_CONCAT with DISTINCT but it didn't help.

Answer 1

So this will pivot and comma delimit your Numbers which I believe is the desired effect? This is a SQL Server solution

declare @t table (OrderedID int, EmpName varchar(50), EmpDep varchar(50), Num varchar(50))

insert into @t
values
(1,'John','Dep1','123')
,(1,'John','Dep1','456')
,(1,'John','Dep2','789')
,(2,'Doug','Dep1','987')
,(2,'Doug','Dep1','654')
,(2,'Steve','Dep2','321')


Select
*
From @t

SELECT distinct e.EmpName,
  e.EmpDep,
  LEFT(r.Num , LEN(r.Num)-1) num
FROM @t e
CROSS APPLY
(
    SELECT r.Num + ', '
    FROM @t r
    where e.EmpName = r.EmpName
      and e.EmpDep = r.EmpDep
    FOR XML PATH('')
) r (Num)

Ouput:

EmpName EmpDep  num
Doug    Dep1    987, 654
John    Dep1    123, 456
John    Dep2    789
Steve   Dep2    321