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[英]PHP / MYSQL - display only left join items in table but concatenate right join values in a column
[英]Concatenate values with LEFT join
在搜索時,我在這里遇到了一個非常相似的帖子,但是我對那里已經發布的內容還有一個疑問。
id|person_name|department_name|phone_number
--+-----------+---------------+------------
1 |"John" |"Finance" |"023451"
1 |"John" |"Finance" |"99478"
1 |"John" |"Finance" |"67890"
1 |"John" |"Marketing" |"023451"
1 |"John" |"Marketing" |"99478"
1 |"John" |"Marketing" |"67890"
2 |"Barbara" |"Finance" |""
3 |"Michelle" |"" |"005634"
可以說我希望最終結果為:
id|person_name|department_name|phone_number
--+-----------+---------------+------------
1 |"John" |"Finance" |"023451", "99478", "67890"
1 |"John" |"Marketing" |"023451", "99478", "67890"
2 |"Barbara" |"Finance" |""
3 |"Michelle" |"" |"005634"
連接的phone_number
結果基本相似; 那你能建議我該怎么辦? 我用DISTINCT嘗試了GROUP_CONCAT,但沒有幫助。
因此,這將導致透視和逗號分隔您的數字,我相信這是理想的效果? 這是一個SQL Server解決方案
declare @t table (OrderedID int, EmpName varchar(50), EmpDep varchar(50), Num varchar(50))
insert into @t
values
(1,'John','Dep1','123')
,(1,'John','Dep1','456')
,(1,'John','Dep2','789')
,(2,'Doug','Dep1','987')
,(2,'Doug','Dep1','654')
,(2,'Steve','Dep2','321')
Select
*
From @t
SELECT distinct e.EmpName,
e.EmpDep,
LEFT(r.Num , LEN(r.Num)-1) num
FROM @t e
CROSS APPLY
(
SELECT r.Num + ', '
FROM @t r
where e.EmpName = r.EmpName
and e.EmpDep = r.EmpDep
FOR XML PATH('')
) r (Num)
輸出:
EmpName EmpDep num
Doug Dep1 987, 654
John Dep1 123, 456
John Dep2 789
Steve Dep2 321
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