如何对包含特殊字符和空格的字符串数组进行排序

Question

I Want to sort an array of string which contains special characters and white spaces. While sorting i want to ignore special characters , so that sorting of array happens based on only characters and digits.

for example : array would be like: ["ibtp-17","personal (z)","personal (a)","(z)","yabcd","y(3)"]

just need smart logic to implement this. Any help would be appreciated. Thanks

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so far i have tried using replace which gives me some times correct result and some times not.

 ["ibtp-17","personal (z)","personal (a)","(z)","yabcd","y(3)"]
 .sort(function(a,b){
    return a.replace(/[^A-Z0-9]/ig, "") > b.replace(/[^A-Z0-9]/ig, "")
 }) 

Answer 1

Since I'm not supposed to just post code (since the OP needs to attempt something by themselves first and all that jazz). Here's some logic:

Array.sort() takes a comparison function. In said comparison function you can put some regex based special character stripper like String.replace(/[^a-zA-Z0-9 ]/g, ""); . and then compare the resultant strings. Cheers.