每天获取第一条记录，然后仅检查条件

Question

I have user attendance CLOCK IN data like this.

id  | userID | created_at
1   | 1      | 2018-06-27 00:15:00
2   | 1      | 2018-06-27 01:43:55
3   | 1      | 2018-06-27 02:43:55
4   | 2      | 2018-06-27 00:15:00
5   | 2      | 2018-06-27 02:43:55
6   | 2      | 2018-06-27 03:43:55
7   | 1      | 2018-06-28 00:55:00
8   | 1      | 2018-06-28 01:43:55
9   | 1      | 2018-06-28 02:43:55
10  | 2      | 2018-06-28 00:00:00
11  | 2      | 2018-06-28 02:43:55
12  | 2      | 2018-06-28 03:43:55

I want a list of dates where user was late to clock in. Assume company work time is 00:00:00 and How can I get results like this :

id  | userID | created_at
1   | 1      | 2018-06-27 00:15:00
4   | 2      | 2018-06-27 00:15:00
7   | 1      | 2018-06-28 00:55:00

Appreciate any help from you guys.Thanks 🙏🏻

Answer 1

You could try conditionally aggregating by user and date, and then checking to see whether an exact midnight clock in occurred (or did not occur):

SELECT
    userID,
    MIN(created_at) AS created_at
FROM yourTable
GROUP BY
    userID,
    DATE(created_at)
HAVING
    SUM(CASE WHEN DATE_FORMAT(created_at, '%H:%i:%s') = '00:00:00' THEN 1 ELSE 0 END) = 0;

Demo