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numpy标准偏差AttributeError:“浮动”对象没有属性“ sqrt”

[英]Numpy Standard Deviation AttributeError: 'Float' object has no attribute 'sqrt'

I know this was asked many times, but, I am still having trouble with the following problem. 我知道这个问题被问过很多次,但是,我仍然无法解决以下问题。 I defined my own functions for mean and stdev, but stdev takes too long to calculate std(Wapproxlist). 我为mean和stdev定义了自己的函数,但是stdev花太长时间才能计算std(Wapproxlist)。 So, I need a solution for the issue. 因此,我需要解决该问题的方法。

import numpy as np
def Taylor_Integration(a, b, mu):
    import sympy as sy
    A, B, rho = sy.symbols('A B rho', real=True)
    Wapp = (A + B*rho - rho/(2*mu*(1 - rho)))**2
    eq1 = sy.diff(sy.integrate(Wapp, (rho, a, b)),A)
    eq2 = sy.diff(sy.integrate(Wapp, (rho, a, b)),B)
    sol = sy.solve([eq1,eq2], [A,B])
    return sol[A], sol[B]

def Wapprox(rho, A, B):
    return A + B*rho

def W(mu, rho):
    return rho/(2*mu*(1-rho))

Wapproxlist = []
Wlist = []
alist = np.linspace(0, 0.98, 10)

for a in alist:
    b = a+0.01; mu = 1
    A, B = Taylor_Integration(a, b, mu)
    rholist = np.linspace(a, b, 100)
    for rho in rholist:
        Wapproxlist.append(Wapprox(rho, A, B))
        Wlist.append(W(mu, rho))

print('mean=%.3f stdv=%.3f' % (np.mean(Wapproxlist), np.std(Wapproxlist)))
print('mean=%.3f stdv=%.3f' % (np.mean(Wlist), np.std(Wlist)))

Output: 输出:

AttributeError                            Traceback (most recent call last)
<ipython-input-83-468c8e1a9f89> in <module>()
----> 1 print('mean=%.3f stdv=%.3f' % (np.mean(Wapproxlist), np.std(Wapproxlist)))
      2 print('mean=%.3f stdv=%.3f' % (np.mean(Wlist), np.std(Wlist)))

C:\Users\2tc\.julia\v0.6\Conda\deps\usr\lib\site-packages\numpy\core\fromnumeric.pyc in std(a, axis, dtype, out, ddof, keepdims)
   3073 
   3074     return _methods._std(a, axis=axis, dtype=dtype, out=out, ddof=ddof,
-> 3075                          **kwargs)
   3076 
   3077 

C:\Users\2tc\.julia\v0.6\Conda\deps\usr\lib\site-packages\numpy\core\_methods.pyc in _std(a, axis, dtype, out, ddof, keepdims)
    140         ret = ret.dtype.type(um.sqrt(ret))
    141     else:
--> 142         ret = um.sqrt(ret)
    143 
    144     return ret

AttributeError: 'Float' object has no attribute 'sqrt'

numpy doesn't know how to handle sympy 's Float type. numpy不知道如何处理sympyFloat类型。

(Pdb) type(Wapproxlist[0])
<class 'sympy.core.numbers.Float'>

Convert it to a numpy array before calling np.mean and np.std . 在调用np.meannp.std之前,将其转换为numpy数组。

Wapproxlist = np.array(Wapproxlist, dtype=np.float64) # can use np.float32 as well

print('mean=%.3f stdv=%.3f' % (np.mean(Wapproxlist), np.std(Wapproxlist)))
print('mean=%.3f stdv=%.3f' % (np.mean(Wlist), np.std(Wlist)))

output: 输出:

mean=4.177 stdv=10.283
mean=4.180 stdv=10.300

Note: If you're looking to speed this up, you'll want to avoid sympy . 注意:如果您希望加快速度,请避免使用sympy Symbolic solvers are pretty cool, but they're also very slow compared to floating point computations. 符号求解器很酷,但是与浮点计算相比,它们也很慢。

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