[英]Python 3.6 open a message box using Tkinter and continue with the script
I have a script that runs a program and then begins a while True
loop. 我有一个运行程序的脚本,然后启动
while True
循环。 I want to open a message box using easyGUI (that simplifies tkinter, so essentially, I want to open a message box using tkinter) and then enter into the while loop. 我想使用easyGUI(简化tkinter,因此从本质上讲,我想使用tkinter打开消息框)打开消息框,然后进入while循环。 When the message box is dismissed, I want to
break
from the loop and then kill the program. 当消息框被驳回,我想
break
由循环,然后杀程序。
My question is, how do I achieve this? 我的问题是,我该如何实现?
Current script (section of): 当前脚本(的部分):
import subprocess, easygui
from time import sleep
f = open("file.txt", "w")
notOpen = True
while True:
if notOpen == True:
subprocess.Popen("program.exe", shell=True, stdout=open(os.devnull, 'wb'))
easygui.msgbox("\nRunning!", "FSRP engine")
notOpen = False
f.write("1=")
f.flush()
sleep(5)
f.write("2=")
f.flush()
sleep(5)
f.write("3")
f.flush()
sleep(5)
You just need to add None
sector. 您只需要添加
None
扇区。
So your code would be: 因此您的代码将是:
import subprocess, easygui
from time import sleep
f = open("file.txt", "w")
notOpen = True
while True:
if notOpen == True:
subprocess.Popen("program.exe", shell=True, stdout=open(os.devnull, 'wb'))
if easygui.msgbox("\nRunning!", "FSRP engine") == 'OK':
notOpen = False
else:
break
f.write("1=")
f.flush()
sleep(5)
f.write("2=")
f.flush()
sleep(5)
f.write("3")
f.flush()
sleep(5)
Or: 要么:
import subprocess, easygui
from time import sleep
f = open("file.txt", "w")
notOpen = True
while True:
if notOpen == True:
subprocess.Popen("program.exe", shell=True, stdout=open(os.devnull, 'wb'))
if easygui.msgbox("\nRunning!", "FSRP engine") == 'OK':
notOpen = False
else:
exit
f.write("1=")
f.flush()
sleep(5)
f.write("2=")
f.flush()
sleep(5)
f.write("3")
f.flush()
sleep(5)
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