简体   繁体   English

Pandas:如何将系列的 MultiIndex 折叠为 DateTimeIndex?

[英]Pandas: how to collapse a Series' MultiIndex to a DateTimeIndex?

As a followup of Pandas groupby: group by semester I need to collapse a Series' MultiIndex to a DateTimeIndex.作为Pandas groupby的后续:按学期分组,我需要将系列的 MultiIndex 折叠为 DateTimeIndex。

I already gave a look at Collapse Pandas MultiIndex to Single Index but at no avail.我已经看过Collapse Pandas MultiIndex to Single Index但无济于事。 I cannot make it work.我不能让它工作。

Series ser is:系列ser是:

dtime  dtime
2016   1        78.0
       7        79.0
2017   1        73.0
       7        79.0
2018   1        79.0
       7        71.0
Name: values, dtype: float64

How to collapse dtime to a single DateTimeIndex?如何将dtime折叠为单个 DateTimeIndex?

dtime
2016-01-01      78.0
2016-07-01      79.0
2017-01-01      73.0
2017-07-01      79.0
2018-01-01      79.0
2018-07-01      71.0
Name: values, dtype: float64

This is the code producing my demo Series ser :这是生成我的演示系列ser的代码:

from datetime import *
import pandas as pd
import numpy as np

np.random.seed(seed=1111)
days = pd.date_range(start="2016-02-15", 
                     end="2018-09-12",
                    freq="2W")

df = pd.DataFrame({"dtime":days, "values":np.random.randint(50, high=80, size=len(days))}).set_index("dtime")

# group by semester
year = df.index.year.astype(int)
month = (df.index.month.astype(int) - 1) // 6 * 6 + 1
grouped = df.groupby([year, month])

ser = grouped.describe()[("values", "max")].rename("values")
print(ser)

You need join levels of MultiIndex or Series together and convert to datetimes :您需要将MultiIndexSeries级别连接在一起并转换为datetimes

idx = ser.index.get_level_values(0).astype(str) +  ser.index.get_level_values(1).astype(str)

ser.index = pd.to_datetime(idx, format='%Y%m')
print(ser)
2016-01-01    78.0
2016-07-01    79.0
2017-01-01    73.0
2017-07-01    79.0
2018-01-01    79.0
2018-07-01    71.0
Name: values, dtype: float64

Or:或者:

dates = pd.to_datetime(year.astype(str) + month.astype(str), format='%Y%m')
grouped = df.groupby(dates)

ser = grouped.describe()[("values", "max")].rename("values")
print (ser)
2016-01-01    78.0
2016-07-01    79.0
2017-01-01    73.0
2017-07-01    79.0
2018-01-01    79.0
2018-07-01    71.0
Name: values, dtype: float64

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM