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承诺在node.js中的while循环中返回

[英]Promise return in while loop in node.js

I am new to node.js programming . 我是node.js编程的新手。 I am confused how the async and await works 我很困惑异步和等待如何工作

const async = require('async');

createUser: async (user, myid) => {
let dotill = false;
let userid = null;

const getreturn = async.whilst(
  function testCondition() { return dotill === false;},
  async function increaseCounter(callback) {
    let sr = "AB" + Math.floor(Math.random() * 99999999999) + 10000000000;
    userid = sr.substr(0, 9);
    await knex.raw('select * from userprofile where user_id=?', [userid]).then((res) => {
      console.log(res.rowCount);
      if (res.rowCount === 0) {
        dotill = true;
        callback;
      }else{
        callback;
      }
    });
  },
  function callback(err, n) {
    if (err) {
      return;
    }
    return {"done":true, "userid":userid}
  }
);

console.log(getreturn); 
// getreturn always undefined iam not getting and return 
}

getreturn is always undefined how i will be able to return in above code or any other way to working in promise.. getreturn始终是不确定的,我将如何以上述代码或任何其他方式返回promise。

async / await is syntactic sugar for functions that chain promises. async / await是链承诺功能的语法糖。 Do not confuse it with the callback-based async.js library, and don't use the latter when working with promises - they don't work together. 不要将其与基于回调的async.js库混淆,也不要在使用async.js时使用后者-它们不能一起工作。 Instead of trying to call async.whilst with more or less appropriate callbacks, just use a plain simple while loop: 与其尝试使用或多或少的适当回调来调用async.whilst ,不如使用简单的while循环:

// const async = require('async'); // remove this!

async createUser(user, myid) {
    let dotill = false;
    let userid = null;

    while (!dotill) {
        const sr = "AB" + Math.floor(Math.random() * 99999999999) + 10000000000;
        userid = sr.substr(0, 9);
        const res = await knex.raw('select * from userprofile where user_id=?', [userid]);
        console.log(res.rowCount);
        if (res.rowCount === 0) {
            dotill = true;
        }
    }
    return {"done":true, "userid":userid};
}

(also you can simplify this to a while (true) { …; if (…) return } loop without that dotill variable) (您也可以将其简化为while (true) { …; if (…) return }循环而没有该dotill变量)

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