如何对两个元组列表求和

Question

list1 = [(1533945600000, 140), (1534032000000, 412), (1534118400000, 364), (1534204800000, 488), (1534291200000, 272), (1534377600000, 350), (1534464000000, 301), (1534550400000, 159), (1534636800000, 224), (1534723200000, 241), (1534809600000, 223), (1534896000000, 175)]


list2 = [(1533945600000, 1516), (1534032000000, 2176), (1534118400000, 2046), (1534204800000, 2400), (1534291200000, 8370), (1534377600000, 2112), (1534464000000, 1441), (1534550400000, 784), (1534636800000, 1391), (1534723200000, 1178), (1534809600000, 1020), (1534896000000, 795)]

How could you combine them into a single list of tuples? considering the first value of the key appears in both lists.

Answer 1

use zip on list1,list2 and then add second value of each tuple:

lst = []
for tup1,tup2 in zip(list1,list2):
    sum_ = tup1[1]+tup2[1]
    lst.append((tup1[0],sum_))

lst

[(1533945600000, 1656),
 (1534032000000, 2588),
 (1534118400000, 2410),
 (1534204800000, 2888),
 (1534291200000, 8642),
 (1534377600000, 2462),
 (1534464000000, 1742),
 (1534550400000, 943),
 (1534636800000, 1615),
 (1534723200000, 1419),
 (1534809600000, 1243),
 (1534896000000, 970)]

Answer 2

You can use the following snippet if the lists are not guaranteed to have the same length or the keys are not guaranteed to be present in both lists or they are not in the same order:

from collections import defaultdict

list1 = [(1533945600000, 140), (1534032000000, 412), (1534118400000, 364), (1534204800000, 488), (1534291200000, 272), (1534377600000, 350), (1534464000000, 301), (1534550400000, 159), (1534636800000, 224), (1534723200000, 241), (1534809600000, 223), (1534896000000, 175)]
list2 = [(1533945600000, 1516), (1534032000000, 2176), (1534118400000, 2046), (1534204800000, 2400), (1534291200000, 8370), (1534377600000, 2112), (1534464000000, 1441), (1534550400000, 784), (1534636800000, 1391), (1534723200000, 1178), (1534809600000, 1020), (1534896000000, 795)]

d = defaultdict(int, list1)
for key, n in list2:                   
    d[key] += n
res = list(map(tuple, d.items()))

res:

[(1533945600000, 1656),
 (1534032000000, 2588),
 (1534118400000, 2410),
 (1534204800000, 2888),
 (1534291200000, 8642),
 (1534377600000, 2462),
 (1534464000000, 1742),
 (1534550400000, 943),
 (1534636800000, 1615),
 (1534723200000, 1419),
 (1534809600000, 1243),
 (1534896000000, 970)]

Answer 3

Using List comprehension with zip :

>>> [(x[0], x[1]+y[1]) for x,y in zip(list1, list2)]

#driver values :

IN : list1 = [(1533945600000, 140), (1534032000000, 412), (1534118400000, 364), (1534204800000, 488), (1534291200000, 272), (1534377600000, 350), (1534464000000, 301), (1534550400000, 159), (1534636800000, 224), (1534723200000, 241), (1534809600000, 223), (1534896000000, 175)]
     list2 = [(1533945600000, 1516), (1534032000000, 2176), (1534118400000, 2046), (1534204800000, 2400), (1534291200000, 8370), (1534377600000, 2112), (1534464000000, 1441), (1534550400000, 784), (1534636800000, 1391), (1534723200000, 1178), (1534809600000, 1020), (1534896000000, 795)]

OUT : [(1533945600000, 1656), (1534032000000, 2588), (1534118400000, 2410), (1534204800000, 2888), (1534291200000, 8642), (1534377600000, 2462), (1534464000000, 1742), (1534550400000, 943), (1534636800000, 1615), (1534723200000, 1419), (1534809600000, 1243), (1534896000000, 970)]

Answer 4

combined_list=[]
for i,j in zip(list1,list2):
     combined_list.append((i[0]+j[0],i[1]+j[1]))